x^2-10x-550=0

Solution for x^2-10x-550=0 equation:

x^2-10x-550=0

a = 1; b = -10; c = -550;
Δ = b2-4ac
Δ = -102-4·1·(-550)
Δ = 2300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2300}=\sqrt{100*23}=\sqrt{100}*\sqrt{23}=10\sqrt{23}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10\sqrt{23}}{2*1}=\frac{10-10\sqrt{23}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10\sqrt{23}}{2*1}=\frac{10+10\sqrt{23}}{2}
$